{-# OPTIONS --lossy-unification #-}
open import Cat.Instances.Sets.Complete
open import Cat.Bi.Instances.Spans
open import Cat.Bi.Diagram.Monad
open import Cat.Instances.Sets
open import Cat.Bi.Base
open import Cat.Prelude

module Cat.Bi.Diagram.Monad.Spans {ℓ} where

open Precategory
open Span-hom
open Span
open Cat.Bi.Instances.Spans (Sets ℓ) using (Underlying-Span)

private module Sb = Prebicategory (Spanᵇ (Sets ℓ) Sets-pullbacks)

Monads in Spans(Sets)🔗

Let $C$ be a strict category. Whatever your favourite strict category might be — it doesn’t matter in this case. Let $C_{0}$ denote its set of objects, and write $C (x, y)$ for its Hom-family. We know that families are equivalently fibrations, so that we may define

C_{1} = x, y : C_{0} \sum C (x, y),

and, since the family is valued in $Sets$ and indexed by a set, so is $C_{1} .$ We can picture $C_{1}$ together with the components of its first projection as a span in the category of sets

Under this presentation, what does the composition operation correspond to? Well, it takes something in the object of composable morphisms, a certain subset of $C_{1} \times C_{1},$ and yields a morphism, i.e. something in $C_{1} .$ Moreover, this commutes with taking source/target: The source of the composition is the source of its first argument, and the target is the target of its second argument. The key observation, that will lead to a new representation of categories, is that the object of composable morphisms is precisely the composition $C_{1} \circ C_{1}$ in the bicategory $Span (Sets)!$

Phrased like this, we see that the composition map gives an associative and unital procedure for mapping $(C_{1} C_{1}) \Rightarrow C_{1}$ in a certain bicategory — a monad in that bicategory.

Spans[Sets] : Prebicategory _ _ _
Spans[Sets] = Spanᵇ (Sets ℓ) Sets-pullbacks

strict-category→span-monad
  : (C : Precategory ℓ ℓ) (cset : is-set (C .Ob))
  → Monad Spans[Sets] (el _ cset)
strict-category→span-monad C cset = m where
  open Monad
  open n-Type (el {n = 2} _ cset) using (H-Level-n-type)
  module C = Precategory C

  homs : Span (Sets ℓ) (el _ cset) (el _ cset)
  homs .apex = el (Σ[ x ∈ C ] Σ[ y ∈ C ] (C .Hom x y)) (hlevel 2)
  homs .left (x , _ , _) = x
  homs .right (_ , y , _) = y

  mult : _ Sb.⇒ _
  mult .map ((x , y , f) , (z , x' , g) , p) =
    z , y , subst (λ e → C.Hom e y) p f C.∘ g
  mult .left = refl
  mult .right = refl

  unit : _ Sb.⇒ _
  unit .map x = x , x , C .id
  unit .left = refl
  unit .right = refl

  m : Monad Spans[Sets] (el (C .Ob) cset)
  m .M = homs
  m .μ = mult
  m .η = unit

It is annoying, but entirely straightforward, to verify that the operations mult and unit defined above do constitute a monad in $Span (Sets) .$ We omit the verification here and instruct the curious reader to check the proof on GitHub.

  m .μ-assoc = Span-hom-path (Sets ℓ) $ funext λ where
    ((w , x , f) , ((y , z , g) , (a , b , h) , p) , q) →
      J' (λ w z q → ∀ (f : C.Hom w x) {y b} (p : y ≡ b) (g : C .Hom y z)
                      (h : C.Hom a b)
                  → (mult Sb.∘ (homs Sb.▶ mult)) .map ((w , x , f) , ((y , z , g) , (a , b , h) , p) , q)
                  ≡ (mult Sb.∘ (mult Sb.◀ homs) Sb.∘ Sb.α← homs homs homs) .map ((w , x , f) , ((y , z , g) , (a , b , h) , p) , q))
         (λ w f → J' (λ y b p → (g : C.Hom y w) (h : C.Hom a b) →
            (mult Sb.∘ (homs Sb.▶ mult)) .map ((w , x , f) , ((y , w , g) , (a , b , h) , p) , refl)
          ≡ (mult Sb.∘ (mult Sb.◀ homs) Sb.∘ Sb.α← homs homs homs) .map ((w , x , f) , ((y , w , g) , (a , b , h) , p) , refl))
          λ y g h → Σ-pathp refl (Σ-pathp refl (C.assoc _ _ _
            ∙ ap₂ C._∘_ (ap₂ C._∘_ (ap (λ p → subst (λ e → C.Hom e x) p f) (hlevel 2 w w _ refl) ∙ transport-refl _)
                                   (ap (λ p → subst (λ e → C.Hom e w) p g) (hlevel 2 y y _ refl) ∙ transport-refl _)
                        ∙ sym ((ap (subst (λ e → C.Hom e x) _)
                                  (ap₂ C._∘_ ((ap (λ p → subst (λ e → C.Hom e x) p f) (hlevel 2 w w _ refl) ∙ transport-refl _))
                                  refl) ∙ ap (λ p → subst (λ e → C.Hom e x) p (f C.∘ g)) (hlevel 2 y y _ refl) ∙ transport-refl _)))
                        refl)))
         q f p g h
  m .μ-unitr = Span-hom-path (Sets ℓ) $ funext λ where
    ((x , y , f) , z , p) →
      J' (λ x z p → (f : C .Hom x y) → (mult Sb.∘ (homs Sb.▶ unit)) .map ((x , y , f) , z , p)
                                     ≡ (x , y , f))
         (λ x f → Σ-pathp refl
            (Σ-pathp refl (ap₂ C._∘_ (ap (λ p → subst (λ e → C.Hom e y) p f) (hlevel 2 _ _ _ _) ∙ transport-refl _) refl
                          ∙ C.idr _)))
         p f
  m .μ-unitl = Span-hom-path (Sets ℓ) $ funext λ where
    (x , (y , z , f) , p) →
      J' (λ x z p → (f : C .Hom y z)
           → (mult Sb.∘ (unit Sb.◀ homs)) .map (x , (y , z , f) , p)
           ≡ (y , z , f))
         (λ x f → Σ-pathp refl
            (Σ-pathp refl (ap₂ C._∘_ (ap (λ p → subst (λ e → C.Hom e x) p C.id) (hlevel 2 _ _ _ _) ∙ transport-refl _) refl
                          ∙ C.idl _)))
         p f

Conversely, if we have an associative and unital method mapping composable morphisms into morphisms, it stands to reason that we should be able to recover a category. Indeed, we can! The verification is once more annoying, but unsurprising. Since it’s less of a nightmare this time around, we include it in full below.

span-monad→strict-category : ∀ (C : Set ℓ) → Monad Spans[Sets] C → Precategory _ _
span-monad→strict-category C monad = precat where
  open Monad monad

  open n-Type C using (H-Level-n-type)
  open n-Type (M .apex) using (H-Level-n-type)

  precat : Precategory _ _
  precat .Ob = ∣ C ∣
  precat .Hom a b = Σ[ s ∈ M ] ((M .left s ≡ a) × (M .right s ≡ b))
  precat .Hom-set x y = hlevel 2
  precat .id {x} = η .map x , sym (happly (η .left) x) , sym (happly (η .right) x)
  precat ._∘_ (f , fs , ft) (g , gs , gt) =
      μ .map (f , g , fs ∙ sym gt)
    , sym (happly (μ .left) _) ∙ gs
    , sym (happly (μ .right) _) ∙ ft

The family of morphisms $Hom (x, y)$ of our recovered category is precisely the fibre of $(s, t) : C_{1} \to C_{0} \times C_{0}$ over the pair $x, y .$ The commutativity conditions for 2-cells in $Span (Sets)$ implies that source and target are preserved through composition, and that the identity morphism — that is, the image of $x$ under the unit map — lies in the fibre over $x, x .$

The verification follows from the monad laws, and it would be trivial in extensional type theory, but the tradeoff for decidable type-checking is having to munge paths sometimes. This is one of those times:

  precat .idr {x} {y} f = Σ-prop-path!
    ( ap (μ .map) (ap (f .fst ,_) (Σ-prop-path! refl))
    ∙ happly (ap map μ-unitr) (f .fst , x , f .snd .fst))
  precat .idl {x} {y} f = Σ-prop-path!
    ( ap (μ .map) (ap (η .map y ,_) (Σ-prop-path! refl))
    ∙ happly (ap map μ-unitl) (y , f .fst , sym (f .snd .snd)))
  precat .assoc f g h = Σ-prop-path!
    ( ap (μ .map) (ap (f .fst ,_) (Σ-prop-path!
        (ap (μ .map) (ap (g .fst ,_)
          (Σ-prop-path! (refl {x = h .fst}))))))
    ∙∙ happly (ap map μ-assoc)
        ( f .fst , (g .fst , h .fst , g .snd .fst ∙ sym (h .snd .snd))
        , f .snd .fst ∙ sym (g .snd .snd)
        )
    ∙∙ ap (μ .map) (Σ-pathp (ap (μ .map) (ap (f .fst ,_)
        (Σ-prop-path! refl)))
           (Σ-pathp refl (is-prop→pathp (λ _ → hlevel 1) _ _))))