module Cat.Displayed.Functor.Adjoint.Total {oa ℓa ob ℓb oe ℓe of ℓf} {A : Precategory oa ℓa} {B : Precategory ob ℓb} {ℰ : Displayed A oe ℓe} {ℱ : Displayed B of ℓf} {L : Functor A B} {R : Functor B A} {L' : Displayed-functor L ℰ ℱ} {R' : Displayed-functor R ℱ ℰ} {L⊣R : L ⊣ R} (L'⊣R' : L' ⊣[ L⊣R ] R') where
Total adjunction🔗
Suppose and are displayed categories, are adjoint functors. A displayed adjunction induces an ordinary adjunction of the corresponding total functors
private module L⊣R = _⊣_ L⊣R module L'⊣R' = _⊣[_]_ L'⊣R' module A = Cr A module B = Cr B module ℱ = Dr ℱ module ℰ = Dr ℰ ∫ℱ = ∫ ℱ module ∫ℱ = Cr ∫ℱ ∫ℰ = ∫ ℰ module ∫ℰ = Cr ∫ℰ ∫ℰF = Cat[ ∫ ℰ , ∫ ℰ ] module ∫ℰF = Cr ∫ℰF ∫ℱF = Cat[ ∫ ℱ , ∫ ℱ ] module ∫ℱF = Cr ∫ℱF
In both the case of the unit and counit, we take the total
natural transformation and compose with the natural isomorphisms
∫ᶠ∘ and ∫ᶠId'≅Id to
adjust the domain and codomain.
∫⊣ : ∫ᶠ L' ⊣ ∫ᶠ R' ∫⊣ .unit = Iso.to ∫ᶠ∘ ∫ℰF.∘ ∫ⁿ (L'⊣R'.unit') ∫ℰF.∘ Iso.from ∫ᶠId'≅Id ∫⊣ .counit = Iso.to ∫ᶠId'≅Id ∫ℱF.∘ ∫ⁿ (L'⊣R'.counit') ∫ℱF.∘ Iso.from ∫ᶠ∘
The zig-zag identities follow from their displayed counterparts after
taking care of the extra identity morphisms due to ∫ᶠ∘ and ∫ᶠId'≅Id.
∫⊣ .zig {x , x'} = ∫Hom-path[] ⌜ ℱ.id' ℱ.∘' L'⊣R'.counit'.ε' (₀' L' x') ℱ.∘' ℱ.id' ⌝ ℱ.∘' ₁' L' (ℰ.id' ℰ.∘' L'⊣R'.unit'.η' x' ℰ.∘' ℰ.id') ℱ.≡[]⟨ apd! (ℱ.idlr' (L'⊣R'.counit'.ε' (₀' L' x'))) ⟩ℱ.≡[] L'⊣R'.counit'.ε' (₀' L' x') ℱ.∘' ₁' L' ⌜ ℰ.id' ℰ.∘' L'⊣R'.unit'.η' x' ℰ.∘' ℰ.id' ⌝ ℱ.≡[]⟨ apd! (ℰ.idlr' (L'⊣R'.unit'.η' x')) ⟩ℱ.≡[] L'⊣R'.counit'.ε' (₀' L' x') ℱ.∘' ₁' L' (L'⊣R'.unit'.η' x') ℱ.≡[]⟨ L'⊣R'.zig' ⟩ℱ.≡[] ℱ.id' ℱ.∎[] ∫⊣ .zag {x , x'} = ∫Hom-path[] ₁' R' (ℱ.id' ℱ.∘' L'⊣R'.counit'.ε' x' ℱ.∘' ℱ.id') ℰ.∘' ⌜ ℰ.id' ℰ.∘' L'⊣R'.unit'.η' (₀' R' x') ℰ.∘' ℰ.id' ⌝ ℰ.≡[]⟨ apd! (ℰ.idlr' (L'⊣R'.unit'.η' (₀' R' x'))) ⟩ℰ.≡[] ₁' R' ⌜ ℱ.id' ℱ.∘' L'⊣R'.counit'.ε' x' ℱ.∘' ℱ.id' ⌝ ℰ.∘' L'⊣R'.unit'.η' (₀' R' x') ℰ.≡[]⟨ apd! (ℱ.idlr' (L'⊣R'.counit'.ε' x')) ⟩ℰ.≡[] ₁' R' (L'⊣R'.counit'.ε' x') ℰ.∘' L'⊣R'.unit'.η' (₀' R' x') ℰ.≡[]⟨ L'⊣R'.zag' ⟩ℰ.≡[] ℰ.id' ℰ.∎[]